Divisor and line bundle
WebRiemann–Roch for line bundles. Using the close correspondence between divisors and holomorphic line bundles on a Riemann surface, the theorem can also be stated in a different, yet equivalent way: let L be a holomorphic line bundle on X. Let (,) denote the space of holomorphic sections of L. WebLinear systems can also be introduced by means of the line bundle or invertible sheaf language. In those terms, divisors (Cartier divisors, to be precise) correspond to line …
Divisor and line bundle
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Webdivisor, Lfor line bundle. Xprojective. Recall that there are many ways of de ning ampleness for line bundle L: (1) some large power is very ample, (2) cohomological … Webabove, and deform the divisor to a linearly equivalent divisor, which does not contain the curve. A more sophisticatedapproach is as follows. If the image of the curve lies in the divisor, then instead of pulling the divisor back, pullback the associated line bundle and take the degree of that D · f C = degf∗O X(D). Definition 2.13.
WebLinear systems can also be introduced by means of the line bundle or invertible sheaf language. In those terms, divisors (Cartier divisors, to be precise) correspond to line bundles, and linear equivalence of two divisors means that the corresponding line bundles are isomorphic. Examples Linear equivalence WebRecall that by DivXwe denote the group of divisors, and there is no ambiguity in this notion if Xis a smooth projective variety. Recall also that if Dis a divisor, then we can associate a line bundle to it, and this line bundle is denoted by O X(D). Theorem 1.2.1. Let Xbe a smooth projective surface. Then there is a unique pairing
Web3 This implies that ord p(f!) = nk+ n 1 = (ord f( )!+ 1)e p(f) 1 which proves our assertion. Proposition 1.1. Let Xbe a compact Riemann surface of genus gand K X be a canonical divisor. Then degK X = 2g 2: Proof. Let fbe a nonconstant meromorphic function on X:Then f: X!P1 is a noncon- stant holomorphic mapping and thus a rami ed covering of … WebTheorem 13. A divisor and a meromorphic section of a holomorphic line bundle are essentially the same thing. More precisely (i) Every holomorphic line L!Xadmits a …
Webisomorphism L!L0of holomorphic line bundles which carries sto s0. (v) Two divisors are linearly equivalent if and only if the corresponding holo-morphic line bundles are isomorphic. (vi) Let Dbe the divisor of a meromorphic section sof a holomorphic line bundle L!X. Then the map L(D) !O(X;L) : f7!fs
WebA complex line bundle is a 2 dimensional vector bundle with a complex structure on each fiber, i.e. each change of coordinates \( g_{ij}: ... 1.2 Divisors, line bundles and sheaves. A holomorphic line bundle is the same as a locally free \( \mathcal{O}_X \)-module of rank 1. sai international school careerWeb1. Line bundle associated to a divisor Given a divisor D= P n pp, recall that we can associate a sheaf O X(D). By construction, when Uis a coordinate disc, O(D)(U) = O X(U) … sai international school codeWebWeil divisors and rational sections of line bundles need not hold. So, to get a nicely behaved theory of divisors on these more general schemes, we apply the \French trick … sai international school bhubaneswar websiteWebThe Divisor-Line Bundle Correspondence So we have a injective homomorphism f(L;s)g=(X;O X)! Cl(X) We can construct an inverse: Let D be a Weil divisor and let L(D) … sai international school bhubaneswar addressWebthere is a divisor D02jmDj, not containing x. But then kD02jkmDj is a divisor not containing x. Pick m 0 such that H0(X;O X(mD)) O X! O X(mD); is surjective for all m m 0. Since … sai international school unwindWeb1. Invertible sheaves and Weil divisors 1 1. INVERTIBLE SHEAVES AND WEIL DIVISORS In the previous section, we saw a link between line bundles and codimension 1 infor-mation. We now continue this theme. The notion of Weil divisors will give a great way of understanding and classifying line bundles, at least on Noetherian normal schemes. sai international school - bhubaneswar emailWebJan 8, 2015 · Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site thick leathery skin on legs